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(x+15)x=8^2
We move all terms to the left:
(x+15)x-(8^2)=0
We add all the numbers together, and all the variables
(x+15)x-64=0
We multiply parentheses
x^2+15x-64=0
a = 1; b = 15; c = -64;
Δ = b2-4ac
Δ = 152-4·1·(-64)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{481}}{2*1}=\frac{-15-\sqrt{481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{481}}{2*1}=\frac{-15+\sqrt{481}}{2} $
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